PHP Dates

[Timer]

Ok... pretend the account timer was made.... (m-d-Y format)
03-20-2009
if the account has been made for more then 30 days... then have a function return the word "done" ... if its not been 30 days... have it return the remaining days till 30 days is up.. is that too hard to ask? :redface:
and can it read the dates from a array please? like
"Timer" => "03-20-2009"
"Hexinist" => "03-21-2009"

Code pl0x? I've tried and failed.. thanks in advance!

[nielsie95]

<?php
$arr["Timer"] = "03-20-2009";
$arr["Hexinist"] = "03-21-2009";
$arr["nielsie95"] = "02-21-2009";

foreach ($arr as $name => $d) {
$ardate = explode("-", $d);
$tdate = mktime(0, 0, 0, $ardate[0], $ardate[1], $ardate[2]);
$togo = 30 - floor((time() - $tdate) / (60 * 60 * 24));

echo "$name => ".(($togo <= 0) ? "done" : "$togo days to go")."<br \>\n";
}
?>

[Bobarkinator]

wow looks like PHP tags need some work.

[Wizzup?]

wow looks like PHP tags need some work.

Blame GeSHi, but I recon I can fix it myself.

[Bobarkinator]

Blame GeSHi, but I recon I can fix it myself.

Weird, I thought GeShi was pretty stable, no?

[Timer]

<?php
$arr["Timer"] = "03-20-2009";
$arr["Hexinist"] = "03-21-2009";
$arr["nielsie95"] = "02-21-2009";

foreach ($arr as $name => $d) {
$ardate = explode("-", $d);
$tdate = mktime(0, 0, 0, $ardate[0], $ardate[1], $ardate[2]);
$togo = 30 - floor((time() - $tdate) / (60 * 60 * 24));

echo "$name => ".(($togo <= 0) ? "done" : "$togo days to go")."<br \>\n";
}
?>

Thanks! :D

Edit..
I modified it a bit..
Now I'm getting..

Warning: mktime() expects parameter 4 to be long, string given in /home/mgate3/public_html/timer/bypass/includes.php on line 7
from this code

<?php
$arr["Timer"] = "03-20-2009";
$arr["Hexinist"] = "03-21-2009";

function DaysLeft($name) {
$ardate = explode("-", $arr[$name]);
$tdate = mktime(0, 0, 0, $ardate[0], $ardate[1], $ardate[2]);
$togo = 30 - floor((time() - $tdate) / (60 * 60 * 24));

if (togo <= 0) {
return "done";
exit;
} else {
return $togo;
}
}
echo DaysLeft("Timer");
?>

[nielsie95]

You can't access the array inside the function..


function DaysLeft($name, $arr) {
$ardate = explode("-", $arr[$name]);
$tdate = mktime(0, 0, 0, $ardate[0], $ardate[1], $ardate[2]);
$togo = 30 - floor((time() - $tdate) / (60 * 60 * 24));

if (togo <= 0) {
return "done";
exit;
} else {
return $togo;
}
}
echo DaysLeft("Timer", $arr);

[Timer]

oh, lol, thanks! :D
EDIT -
Now.. its really messed up.. no matter what, it returns done..


<?php
$arr["Timer"] = "03-10-2009";
$arr["Hexinist"] = "03-21-2009";

function DaysLeft($name, $arr) {

$ardate = explode("-", $arr[$name]);
$tdate = mktime(0, 0, 0, $ardate[0], $ardate[1], $ardate[2]);
$togo = 30 - floor((time() - $tdate) / (60 * 60 * 24));

if (togo <= 0) {
return "done";
} else {
return $togo;
}
}

echo DaysLeft("Timer", $arr);
?>

[nielsie95]

How long did you try it for yourself..? :\


if ($togo <= 0) {

[Timer]

lol, wow.. i totally didn't notice that... :o