Sin

03-07-2013, 12:46 AM

So hey guys, this test came up on my test today and am wondering if I did it right:

An area of a square has the equation of 16x^2 - 24x + 9. Find the perimeter of the square.

What I did

Factored the equation into s^2 = A[]

(4x-3)(4x-3) = 16x2 -12x - 12x + 9 = (4x-3)^2

Since the perimeter of a square is 4s, am i correct in doing

(4x-3)(4) = 16x-12

P = 16x - 12?

An area of a square has the equation of 16x^2 - 24x + 9. Find the perimeter of the square.

What I did

Factored the equation into s^2 = A[]

(4x-3)(4x-3) = 16x2 -12x - 12x + 9 = (4x-3)^2

Since the perimeter of a square is 4s, am i correct in doing

(4x-3)(4) = 16x-12

P = 16x - 12?