Well, i'm learning the whole , SIN COS TAN thing, and i get it for the most part, but for some reason, im confused on this one problem..
http://img705.imageshack.us/img705/9428/trig.png
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Well, i'm learning the whole , SIN COS TAN thing, and i get it for the most part, but for some reason, im confused on this one problem..
http://img705.imageshack.us/img705/9428/trig.png
i r stupod.
Presumably there's a right angle where side x and the side going across the top meet, so there's a total of 90 degrees being shared by those two angles. The second angle should have a measurement of 22 degrees. Since you have an opposite and adjacent angle, you can use tangent, so you'll set up your equation like this:
tan(22) = 20/x
which then simplifies to:
x = 20/tan22
which can be worked out on a calculator.
It's just simple trigonometry? :confused:
Inside angle on the top is 22*.
tan(22) = 20 / x
0.40403 = 20 / x
0.40403x = 20
x = 49.502
EDIT: Waah, Method winz
He doesn't need to use the law of sines YoHoJo???
Thanks for your guys help, i had no clue ...
what do you need trig for? basic algebra could have solved it using pythag. :D
e: nvm. 20 is an angle, not a side :duh:
Cause 22 is a angle..
Ahh you guys ended up doing it wrong, oh well.. My teacher said
Since the top line and the bottom line of the triangle are parallel, and theres a transveral in the middle of them(making a Z) then the top degree is the EXACT same as the angle of the triangle(bottom left) so the bottom left would be 68 degrees, and then thats how i was supposed to solve :(.. Oh well, thanks anyway.
well If I would have seen this you would have gotten the right answer :p
sorry, lol.
i didn't even read the thread, tangent works too as the people above explained.
weird...I hate it when teachers want it done a certain way and ignore right ways that are different...
Meh, your diagram doesnt show they are parallel.
line A||B would have done...
Have have you ever considered it could be the teacher that was wrong?