This is a practice exam for the calculus course at the university I've applied.
I will attempt some question tomorrow!
This is a practice exam for the calculus course at the university I've applied.
I will attempt some question tomorrow!
Oh Hai Dar
Im getting headache when i look at it :S
These aren't hard... If you take the course.
Writing an SRL Member Application | [Updated] Pascal Scripting Statements
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Progress Report:13:46 <@BenLand100> <SourceCode> @BenLand100: what you have just said shows you have serious physchological problems 13:46 <@BenLand100> HE GETS IT! 13:46 <@BenLand100> HE FINALLY GETS IT!!!!1
The limit ones are crazy.the integral is just split the thing from b to a -> -(0 to b) and 0 to a.
Oh Hai Dar
The limits are merely applications of l'Hospital's rule, one is a Renault sum, then logarithm rules simplify easily..
Writing an SRL Member Application | [Updated] Pascal Scripting Statements
My GitHub
Progress Report:13:46 <@BenLand100> <SourceCode> @BenLand100: what you have just said shows you have serious physchological problems 13:46 <@BenLand100> HE GETS IT! 13:46 <@BenLand100> HE FINALLY GETS IT!!!!1
Wow.. I need to use my brain more...
do you mean riemann sum? or something else?
Last edited by Main; 05-11-2010 at 02:42 AM.
Oh Hai Dar
Writing an SRL Member Application | [Updated] Pascal Scripting Statements
My GitHub
Progress Report:13:46 <@BenLand100> <SourceCode> @BenLand100: what you have just said shows you have serious physchological problems 13:46 <@BenLand100> HE GETS IT! 13:46 <@BenLand100> HE FINALLY GETS IT!!!!1
Writing an SRL Member Application | [Updated] Pascal Scripting Statements
My GitHub
Progress Report:13:46 <@BenLand100> <SourceCode> @BenLand100: what you have just said shows you have serious physchological problems 13:46 <@BenLand100> HE GETS IT! 13:46 <@BenLand100> HE FINALLY GETS IT!!!!1
This example is very useful for basic level students. They can easily learn that calculus and also they can get benefit from them.
Gravedig, thus closed.
1a ln(0) is undefined
1b (x-1) = 0 for x=1, you can't divide by 0
1c see above, can't divide by 0
1d infinite sums are hard to do
(cbf to do the rest)
I made a new script, check it out!.
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