Page 1 of 3 123 LastLast
Results 1 to 25 of 51

Thread: Math Help Please!

  1. #1
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Math Help Please!

    took out old questions

    edited on feb 19 09

    could someone please factor this for me:

    2x^2-7x+3

    Thanks.
    ill rep.

    AND HERE ARE MORE:
    http://answers.yahoo.com/question/in...9202742AAwxbLm

  2. #2
    Join Date
    Apr 2007
    Location
    Perth, Australia
    Posts
    3,926
    Mentioned
    3 Post(s)
    Quoted
    2 Post(s)

    Default

    SCAR Code:
    s<2 = s<4  //opposites are equal
    x - 21 = 3x -5
         x = 16
       s<2 = 4(16) - 21
           = 43    //size of angles 2 and 4 is 43 degrees

       s<3 = s<1

       360 = s<1 + s<3 + s<2 + s<4    //all angles must equal 360 degrees
           = 2*s<1 + 2*s<2       //since opposites are equal
           = 2s<1 + 2(43)
           = 2s<1 + 86
      2s<1 = 360 - 86
           = 274
       s<1 = 274/2
           = 137 degrees   //ANSWER

    I'm pretty sure its correct. Narcle's working is also correct except 4*16 - 21 = 43 not 42

  3. #3
    Join Date
    Sep 2007
    Location
    Michigan
    Posts
    3,862
    Mentioned
    2 Post(s)
    Quoted
    1 Post(s)

    Default

    m<2 = M<4

    4x-21=3x-5
    x-21=-5
    x=16

    4*16-21=42

    180-42=138
    m<1=138

    I think, so many people on this thread atm lol
    (Scripts outdated until I update for new SRL changes)
    AK Smelter & Crafter [SRL-Stats] - Fast Fighter [TUT] [SRL-Stats]
    If you PM me with a stupid question or one listed in FAQ I will NOT respond. -Narcle
    Summer = me busy, won't be around much.

  4. #4
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    Quote Originally Posted by Narcle View Post
    m<2 = M<4

    4x-21=3x-5
    x-21=-5
    x=16

    4*16-21=42

    180-42=138
    m<1=138

    I think, so many people on this thread atm lol
    OMG NARCLE I LOVE YOU!!!!!!
    thanks oh yeah btw you made a mistake
    4*16-21=43
    not 42

    THANKS AGAIN REP++ too you ill post more problems here in a sec thanks! dum me

  5. #5
    Join Date
    Sep 2007
    Location
    Michigan
    Posts
    3,862
    Mentioned
    2 Post(s)
    Quoted
    1 Post(s)

    Default

    Quote Originally Posted by p1nky View Post
    OMG NARCLE I LOVE YOU!!!!!!
    thanks oh yeah btw you made a mistake
    4*16-21=43
    not 42

    THANKS AGAIN REP++ too you ill post more problems here in a sec thanks! dum me
    oops yeah spelling error
    (Scripts outdated until I update for new SRL changes)
    AK Smelter & Crafter [SRL-Stats] - Fast Fighter [TUT] [SRL-Stats]
    If you PM me with a stupid question or one listed in FAQ I will NOT respond. -Narcle
    Summer = me busy, won't be around much.

  6. #6
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    K I Posted Next Question Please Help On That Too !

    REP++ TO ZEP THANKS! for other formula tho narcles shorter and easier thanks again

  7. #7
    Join Date
    Dec 2006
    Location
    Canada
    Posts
    17
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)
    Ok this is how you do the second question.

    Since all sides are equal to each other you seperate the x and y:

    First step we find out what x is:

    2x-6 = 5x
    2x-5x-6=0
    2x-5x=6
    -3x=6
    x=-2 (Divide both sides by -3)


    Second Step we find out what y is:

    5y = 7y+7
    5y-7y=7
    -2y=7
    y=-7/2 (Divide both sides by -2)


    So the answer would be

    x= -2, y= -7/2

    *If you want to find the length of each side
    just substitute the x with -2 and the y with -7/2*





    Cheers!

  8. #8
    Join Date
    Apr 2007
    Location
    Perth, Australia
    Posts
    3,926
    Mentioned
    3 Post(s)
    Quoted
    2 Post(s)

    Default

    SCAR Code:
    5x = 7y + 7             2x - 6 = 5y
     x = (7y + 7)/5
     
    Substitute into the other equation:
    2(7y + 7)/5 - 6 = 5y
    (14y + 14)/5 - 6 = 5y
    (14y + 14)/5 = 5y + 6
    14y + 14 = 25y + 30
    11y = -16
      y = -16/11
      x = (7y + 7)/5
        = (7(-16/11) + 7)/5
        = -7/11

    *Hint: use a graphics calculator and solve use the simultaneous solver.

    EDIT:
    Quote Originally Posted by foolishpaper View Post
    Since all sides are equal to each other you seperate the x and y:
    Are they all equal?

  9. #9
    Join Date
    Dec 2006
    Location
    Canada
    Posts
    17
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Quote Originally Posted by ZephyrsFury View Post
    SCAR Code:
    5x = 7y + 7             2x - 6 = 5y
     x = (7y + 7)/5
     
    Substitute into the other equation:
    2(7y + 7)/5 - 6 = 5y
    (14y + 14)/5 - 6 = 5y
    (14y + 14)/5 = 5y + 6
    14y + 14 = 25y + 30
    11y = -16
      y = -16/11
      x = (7y + 7)/5
        = (7(-16/11) + 7)/5
        = -7/11

    *Hint: use a graphics calculator and solve use the simultaneous solver.

    EDIT:


    Are they all equal?
    I think so because the square in each corner means all sides are equal. If they not equal then ur answer is the right one

  10. #10
    Join Date
    Apr 2007
    Location
    Perth, Australia
    Posts
    3,926
    Mentioned
    3 Post(s)
    Quoted
    2 Post(s)

    Default

    No it means its a right angle. But a rectangle has right angles in every corner yet it doesn't have to have equal sides.

  11. #11
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    thanks foolish

    you deserve srl junior ill rep you thansk alot

  12. #12
    Join Date
    Dec 2006
    Location
    Canada
    Posts
    17
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Quote Originally Posted by ZephyrsFury View Post
    No it means its a right angle. But a rectangle has right angles in every corner yet it doesn't have to have equal sides.
    Oh! I see now. So yea Zephyrs' answer is the right one p1nky!

  13. #13
    Join Date
    Mar 2007
    Posts
    915
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Quote Originally Posted by foolishpaper View Post
    I think so because the square in each corner means all sides are equal. If they not equal then ur answer is the right one
    You're wrong!

    The square in each corner means every angle is 90 degrees...which it is in a rectangle...

    Sig by oldschool .html

    Earn money for free!

  14. #14
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    i think you did it wrong
    its

    2x-6=5y

    and

    7y+7=5x

    and i dont know how to solve that...

    i still didnt get it seeing zephs explanation :S

  15. #15
    Join Date
    Dec 2006
    Location
    Canada
    Posts
    17
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Quote Originally Posted by lakerzz8 View Post
    You're wrong!

    The square in each corner means every angle is 90 degrees...which it is in a rectangle...
    Yea like i said before my bad. Anyways, look at zephyrs' it is the right one. My answers are only right if the shape is a square and not a rectangle!

  16. #16
    Join Date
    Sep 2007
    Location
    Michigan
    Posts
    3,862
    Mentioned
    2 Post(s)
    Quoted
    1 Post(s)

    Default

    I was getting -7/11 for X as well.
    Does it fit into it?
    (Scripts outdated until I update for new SRL changes)
    AK Smelter & Crafter [SRL-Stats] - Fast Fighter [TUT] [SRL-Stats]
    If you PM me with a stupid question or one listed in FAQ I will NOT respond. -Narcle
    Summer = me busy, won't be around much.

  17. #17
    Join Date
    Dec 2006
    Location
    Canada
    Posts
    17
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    [QUOTE=ZephyrsFury;354539]
    SCAR Code:
    5x = 7y + 7             2x - 6 = 5y
     x = (7y + 7)/5
     
    Substitute into the other equation:
    2(7y + 7)/5 - 6 = 5y
    (14y + 14)/5 - 6 = 5y
    (14y + 14)/5 = 5y + 6
    14y + 14 = 25y + 30
    11y = -16
      y = -16/11
      x = (7y + 7)/5
        = (7(-16/11) + 7)/5
        = -7/11

    *Hint: use a graphics calculator and solve use the simultaneous solver.

    QUOTE]

    Just look at how Zephyr did it. His answers are correct. P1nky, you can look at mine only if there is going to be square shaped questions on the test. Good Luck tomorrow!

  18. #18
    Join Date
    Mar 2008
    Location
    Western Canada
    Posts
    208
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Lol I'm in Grade 7 but im justing learning this stuff.It suczors.If you need more help just PM me I'll be glad to help

  19. #19
    Join Date
    Dec 2007
    Location
    Williston, ND
    Posts
    3,106
    Mentioned
    0 Post(s)
    Quoted
    3 Post(s)

    Default

    Yeah, so on the bottom one, if you still dont understand Zephyrs's:
    bottom side = top side
    left side = right side
    so then:

    2x-6 = 5y
    5x = 7y+7

    So solve for one variable on both of the equations

    (top) 2x = 5y-6 ------> x = (5y-6)/2
    (bottom) x= (7y+7)/5

    since you know that x = x because they are the same variable.....

    (7y+7)/5 = (5y-6)/2

    and now solve for y (in this case I would cross multiply)

    5*(5y-6) = 2*(7y+7)

    distribute the coefficients.....

    25y-35 = 14y + 14 //////////OMG!!!!!!!! 5*6 doesn't equal 35!!!!
    I hate myself.......... so I'll restart with the right equation..... at the bottom, so you can see my mistakes.....


    25y-35 = 14y+14

    solve for y

    25y = 14y+14+35
    25y-14y = 14+35
    11y = 49

    therefore:

    (((((((((((((((((((((((((((((((y = 49/11)))))))))))))))))))))))))))))))))))))

    now that you have y, stick it one of your other equations and get x

    7y+7 = 5x

    7(49/11)+7 = 5x

    343/11 + 77/11 = 5x 77/11 = 7

    420/11 = 5x divide by 5, and you're golden

    420/55 = x (might wanna simplify)

    (((((((((((((((((((((((((((((((x = 84/11)))))))))))))))))))))))



    hope I'm right.........wouldn't look good if a kid in calc II failed geometry.....

    EDIT!!!!


    25y-30 = 14y+14

    solve for y

    25y = 14y+14+30
    25y-14y = 14+30
    11y = 44

    therefore:

    (((((((((((((((((((((((((((((((y = 4)))))))))))))))))))))))))))))))))))))

    now that you have y, stick it one of your other equations and get x

    7y+7 = 5x

    7(4)+7 = 5x

    28 + 7 = 5x

    35 = 5x divide by 5, and you're golden

    7 = x

    (((((((((((((((((((((((((((((((x = 7)))))))))))))))))))))))))))


    sorry for the mistake...stupid me...stupid multiplication!
    Proud owner of "Efferator" my totally boted main account!
    "You see, sometimes, science is not a guess" -Xiaobing Zhou (my past physics professor, with heavy Chinese accent)

  20. #20
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    OK GUYS i edited and added new questions i need help with


    THANKS ILL REP I NEED IT BY 2NITE lol test 2mooro

    thanks again

  21. #21
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    cmon anyone?

  22. #22
    Join Date
    Dec 2006
    Location
    Minnesota
    Posts
    227
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    1)
    The first one is a right triangle. It is because when you plug the two smaller numbers into the Pythagorean Theorum(A^2 * B^2 = C^2) It gives you the third number

    Now the second part is acute because the two smaller numbers squared and added together is 181. Then, 13 squared is 169. Since the square root of 181 is bigger than the square root of 169, the triangle is acute, because to be right, that third large side would have to be the square root of 181 long.

    2) I am 90% sure the area is 90.

    Ok. If you took the places where the lines come together on the side and drew from there to the center point, all the way around, they would all be equilateral triangles(equal side lengths). Knowing that, all we need is the height if that line drew in to the center on your picture, and we know the area of that 1 triangle. Multiply times 6 to get the whole thing.

    -Illustration:
    -------/|\
    -----/--|-\
    -A--/--|--\
    ---/----|---\ B
    --/---D|----\
    -/------|-----\
    -___________
    -------C

    (Had to put in the hashes so it would post right)

    Lines A, B, and C are all the same length, 6. So, we need to find the length of line D. Ok, so using the pythagorean theorum, A(Hypotenuse) squared is 36, minus half of C which is 3, so 9 when you square. 36 - 9 = 25. Square root is 5. That is the length of line D. So, to find the area of the triangle, take half of C (3) times the height D (5). You get 15 as the area of the triangle.

    Now, there are 6 triangles in your polygon, so multiply times 6, and you get 90!

    Hope I made sense with all that. Feel free to ask questions.


    - 9th Grader

  23. #23
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    REP++ thanks but the second 1 was kind of confuzing :S

    ADDED ANOTHER QUESTION

  24. #24
    Join Date
    Dec 2006
    Location
    Minnesota
    Posts
    227
    Mentioned
    0 Post(s)
    Quoted
    0 Post(s)

    Default

    Ok, can you give me any more of a specific are that you can't get?

    You are basicly finding that length of the line drawn up to the center, in order to find the area of 1 section (triangle) with the pythagorean theorum.

    Then you multiply by the number of sections (triangles) you have in your polygon(also the number of sides) to find the total area.

    I gotta get to bed, but i'll be back tomorrow, I promise.

  25. #25
    Join Date
    Dec 2006
    Location
    Program TEXAS home of AUTOERS
    Posts
    7,934
    Mentioned
    26 Post(s)
    Quoted
    237 Post(s)

    Default

    alrite goodnight hopefully someelse can help for some other questions

    thanks rockman i think i get the second not sure though

Page 1 of 3 123 LastLast

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Similar Threads

  1. Math Help!
    By I Karma I in forum OSR Help
    Replies: 8
    Last Post: 05-31-2007, 09:07 AM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •