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Thread: 0.999...=1

  1. #51
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    Look, I've been thinking about this issue for a whole damn day straight now.

    No matter how you put it, the difference between between 0.99.. and 1 will always remain as the 1^-..infinity (..0001). As long as there is some difference, the numbers aren't identical, and hence, 0.99.. is not the same as 1.

  2. #52
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    Nope.

    Difference between 0.99 and 1 is 0.01. Difference between 0.999 and 1 is 0.001. Difference between 0.9999 and 1 is 0.0001. With each 9 you add, you add a 0 before you get to the 1. So if the 9s never stop, you never stop adding 0s, and you never get to the 1.

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    Quote Originally Posted by EvilChicken! View Post
    Look, I've been thinking about this issue for a whole damn day straight now.

    No matter how you put it, the difference between between 0.99.. and 1 will always remain as the 1^-..infinity (..0001). As long as there is some difference, the numbers aren't identical, and hence, 0.99.. is not the same as 1.
    If you have an infinite number of digits, How do you tack a number on the end? You can't The 0s never end so the 1 never exists at the end. If the difference is infinitely small, it is non-existent.

  4. #54
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    I +1 boberman's response.

    If the 0's are infinite, there is no end. How can you put something on the end of something that doesn't end?

  5. #55
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    Quote Originally Posted by TViYH View Post
    I +1 boberman's response.
    *cough* 9 minutes *cough*

  6. #56
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    Boberman, so by your logic any number with continuing digits = a different number simply because the .01 wouldn't have a chance to be placed is physical terms?

    "If you have an infinite number of digits, How do you tack a number on the end? You can't The 0s never end so the 1 never exists at the end. If the difference is infinitely small, it is non-existent."

    This logic goes against your algebra.
    ****_
    So .89, by your logic must = .9 because that last digit would never be "tracked."

    Algebra disproves this because

    x = .8999...
    10x = 8.999...
    8.9 - x = 8.099...1, not .9 as with what happens with .99...


    I am not here to disprove that .999... = 1. I simply saw a flaw in bober's logic, which implied that any repeating 9 = something larger.
    No room for thoughts.

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    Quote Originally Posted by A G E N T View Post
    Where I disagree is:
    9.999999...-0.999999...=9

    Since you don't know the decimal place of either number to any precision, you can't know the decimal precision of the answer either. Maybe I'm wrong, but that's just the way I see it.
    Good point, I'd love to see an answer to this one.
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  8. #58
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    Brown: We're talking about .9, not .89.

    A G E N T: To my knowledge, any number (positive) subtracted by itself is 0.

  9. #59
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    Quote Originally Posted by Brown View Post
    Boberman, so by your logic any number with continuing digits = a different number simply because the .01 wouldn't have a chance to be placed is physical terms?

    "If you have an infinite number of digits, How do you tack a number on the end? You can't The 0s never end so the 1 never exists at the end. If the difference is infinitely small, it is non-existent."

    This logic goes against your algebra.
    ****_
    So .89, by your logic must = .9 because that last digit would never be "tracked."

    Algebra disproves this because

    x = .8999...
    10x = 8.999...
    8.9 - x = 8.099...1, not .9 as with what happens with .99...


    I am not here to disprove that .999... = 1. I simply saw a flaw in bober's logic, which implied that any repeating 9 = something larger.
    Algebra confirms it, if you do correct algebra, if you use incorrect algebra then you can say whatever you want, though it doesn't prove or disprove anything.

    First off, 8.9 - .89999 != 8.09991, it is equal to 8.00001. Therefore, 8.9 - .899.... is equal to, surprise 8. because that .8999.. is equivalent to saying .9.

    Next time, check your algebra before saying it disproves anything. You can't say that there is a number at the end of an infinite sequence, by saying that you are saying your sequence isn't infinite. (infinite BY DEFINITION means never ending). A 1 after and infinite number of zeros doesn't exist because those zeros don't end. Heck, we might as well put pi, e, or ln(pi^e) in there, it doesn't matter because they don't exist.

    Infinity is less of a number and more of a concept (a very strange concept the deeper you go into the rabbits hole, Look up cantor and his theories on infinity). If you don't have a cursory understanding on what infinity is and implies, then yes this won't make sense to you. However, you can trust me and every other person with a PHd in Mathematics that .999.... is in fact = 1.

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    10/3 = 3.33..
    10/30 = .33..
    .33.. x 3 = .99..
    therefore..
    3*10/30 = .99
    30/30 = .99..
    1/1 = .99..
    1 = 0.99..

    figured that mehord out my self

  11. #61
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    0.999... = 1 and 0.999... <> 1?

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    0.9 recurring can be proved by mathematically logical steps to be equal to 1

    this has been known since the time of ancient greeks.
    i dont even know why we're debating about this, its not anyones opinion, this is a mathematical fact, theres no room for debate or interpreting.


    the only time I've ever debated against maths was satirically saying that pi = 3, which was only to point out the flawed attidute of religion.
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  13. #63
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    pi equals three when I need to draw a sinus graph ^_^.
    Verrekte Koekwous

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