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Thread: Quadratic Equation

  1. #1
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    Default Quadratic Equation

    I need to solve this problem using the quadratic formula, but it's not in the quadratic equation yet. I don't need you to solve this problem, would just like you to show me it in the quadratic equation form and how you got it there.

    What I have: 4/v = v-6/v-4

    Need it in: ax^2 + bx + c form

    thanks for any help, you will get rep+ if you make an honest attempt at trying to help.

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    Default

    multiply every term by v

    add/subtract to get it all on one side
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    Default

    Do you really need to get this in the quadratic equitation, or do you only need to solve this?
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    Default

    4v -16 =v^2 -6v In quadratic mode is v^2 -10v + 16
    to get there you start with (assuming you just forgot the paranthesis)
    4/v = (v-6)/v-4

    multiply both sides by v and you get

    4 = (v^2 -6v)/v-4 which gets rid of the v in the denomineter on the left side

    next mulitply both sides by v-4 to get the v out of the denomenter on the right side

    4v - 16 = v^2 - 6v

    next put all terms on one side

    0 = v^2 - 10v + 16 hence you get you're equation
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    Default

    I think the parenthesis go:

    4/v = v-(6/v)-4

    That's how you would do it without the parenthesis according to the order of operations
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    Default

    Quote Originally Posted by Markus View Post
    Do you really need to get this in the quadratic equitation, or do you only need to solve this?
    I need to solve it, but I need to solve it using the quadratic formula. The way we learned it is x:= -b sqrt(b^2 - 4ac) all over 2a. lol at my bits of scar in there (:= and sqrt) but anyway, yea I just needed to get this into ax^2 + bx + c so that I could solve it the way the teacher wanted.'

    edit: I don't think multiplying by v gets rid of the v on the right where it's v-6 over v-4, I think to get rid of that you have to multiply by the conjugate, no? which is why I posted here to see if anyone could confirm this. and then wouldn't that mess up the v on the left side?

    EDIT: I think barbarianl3t is right. I'll just go with that and if it's wrong my teacher can tell me how I was supposed to do it, thanks for your help everyone.
    Last edited by Baked0420; 09-24-2009 at 07:22 AM.

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    Default

    You just need to find the common denominator for both sides, which is (v)(v - 4), so you multiply both sides by those two values, which is what barbarianl3t mentioned.
    :-)

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    yea, for some reason before I posted I thought I'd need to multiply by a conjugate, no clue why, but after barb's post, I realized when I thought maybe just multiplying by v-4 was right, but I thought that'd mess up the other side of the equation but it won't change the denominator shoulda just tried it, well thanks for the help Method and barbarianl3t, and thanks for confirming it Method.

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