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Thread: It's just a quadradic...Need Help!

  1. #1
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    Default It's just a quadradic...Need Help!

    Hey Guys, been awhile since I've been back here. Simba 0.97!

    Anyways, I have a problem that I need help with. The question is about finding fuel efficiency (distance / fuel used) for a vehicle. So here's the given equation.
    1. f(s) = (s - 10)^2 + 9900
    f(s) represents the fuel consumption rate in (milliliters per hour)
    s represents the speed of the vehicle in (kilometers per hour)

    The answer needed is in (distance/fuel used), and must be the most efficient at that.

    Well. Help would be very much appreciated!
    Thanks,

    ~mrpickle

  2. #2
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    Default

    okay i got it distance = speed * time
    and fuel used = rate * time
    so st/f(s)t simplifies to s/f(s)
    so use s as x and graph it.
    x/((x-10)^2+9900)
    then find maximum which is x = 100
    plug into the consumption rate and get 18000
    then put into distance over fuel used
    100t/18000t
    simplify to 1km/180ml

  3. #3
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    THAT MAKES SENSE! lol. I couldn't figure it out in 1h... and then gave up xD.
    Thanks again

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