Ok so I've tried to do these problem multiple times and every time I get the wrong answer
1. A basketball player makes a jump shot giving the ball a velocity of 10.0 m/s at 60(deg)N of E. Assume the ball is released at the same height as the basket. How far away from the basket was he when he made his shot
Book answer: 8.85 m
My answer: 4.4 m
My work
viy = sin(60)10 = 8.67
Vx = cos(60)10 = 5
a = -9.8
The rest I am unsure of, but I get 4.4m I set Vf equal to 0 and solved.
2. A daredevil is shot out of a cannon at 45(deg) N of E with an initial velocity of 25m/s. A net is position at a horizontal distance of 50.0m. At what height above the cannon should the net be positioned in order to catch the daredevil?
Book answer: 10.9m
My answer: 11.08m
My work
Vx = cos(45)25 = 17.68
Viy = sin(45)25 = 17.68
Change in X = 50
a = -9.8
t = 2.8 sec (found this on out using a formula) 17.68 = 50/t
3. (I just cannot figure this one out!)
You throw a softball at an unknown angle (N of E). It's in the air for 4 seconds total and travels 50m horizontally, calculate the velocity of the ball in MPH and the angle it was thrown at. Assume it landed at the same height.
Any help is greatly appreciated!