Originally Posted by
kevin33
You cant have a fraction in a fraction so you simply find a common denominator for the top then the bottom (top is cosy, bottom is siny) then change it to 1 term (change 1). With 1 term on top and 1 term on the bottom, you then, instead of divide, invert and multiply. The numerator and denominators are the same (cosysiny) so they cancel out leaving you with the answer which matches the RHS.
To sum it all up, cosy = 1 and siny = 1 is clearly not what I did so you have interpreted it wrong. cosy/cosy and siny/siny is what I have and each equal the previous 1, they are just combined with the 2nd term
The way you approached the question was very confusing for me since you changed the right-hand side, but if that's how you do it in your country then I take back whatever I said against that.
Ok so I see what you did there
sinY(cosY+sinY)
_______________
cosY(sinY+cosY) etc.
Nevertheless, you still need brackets!
Take this as an example...
1 + 2 x 3 / 4 (=2.5) is not the same as (1+2x3)/4 (=1.75)
Type it in your calculator if you don't believe me.
Based on that,
1+ (siny/cosy) / 1+ cosy/siny
is not the same as
(1+(siny)/(cosy))/(1+(cosy)/(siny))
And yes, you can have a fraction within a fraction?
Here's what I found on 'complex fractions':
HTML Code:
http://www.sosmath.com/algebra/fraction/frac4/frac4.html
HTML Code:
http://www.purplemath.com/modules/compfrac.htm
Thanks though for sharing - didn't mean to offend you.
We're probably the only 2 people following this thread haha...